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ScatterPlot ScatterPlot Select the x-Variable Sepal.Length Sepal.Width Petal.Length Petal.Width Select the y-Variable Sepal.Length Sepal.Width Petal.Length Petal.Width Select the file png pdf Download the Plot

Chapter 5 : Functions & Pointers (Let us C)

Write a function to calculate the factorial value of any integerentered through the keyboard. #include <stdio.h> main() { int a, f; printf("enter any number="); scanf("%d",&a); f=fact(a); printf("%d!=%d",a,f); } fact(int x) { int i,f=1; for(i=x;i>=1;i--) { f=f*i; } } Output: enter any number=33 33!=-2147483648

Let Us C / Chapter 4 (The Case Control Structure)

Programming Solutions ( By:MK )                                 Exercise [C] Write a menu driven program which has following options: 1. Factorial of a number. 2. Prime or not 3. Odd or even 4. Exit                           Solution: #include<stdio.h> #include<conio.h> main() { int num,i,j=0,k=0,choice,fact=1; clrscr(); printf("Please enter any number: "); scanf("%d",&num); while(1) { printf("\n\n1. Factorial"); printf("\n2. Prime"); printf("\n3. Odd/Even"); printf("\n4. Exit"); printf("\n\nPlease enter your choice:  "); scanf("%d",&choice); switch(choice) { case 1:      for(i=num;i>=1;i--) {      fact=fact*i;      }      printf("\nFactorial = %d ",fact);      break; case 2:   ...

According to a study, the approximate level of intelligence of a person can be calculated using the following formula: i = 2 + ( y + 0.5 x ) Write a program, which will produce a table of values of i, y and x, where y varies from 1 to 6, and, for each value of y, x varies from 5.5 to 12.5 in steps of 0.5.

According to a study, the approximate level of intelligence of a person can be calculated using the following formula: i = 2 + ( y + 0.5 x ) Write a program, which will produce a table of values of i, y and x, where y varies from 1 to 6, and, for each value of y, x varies from 5.5 to 12.5 in steps of 0.5.  Let C Solution: #include<stdio.h> main() { int y; float i,x;    for (y=1; y<=6; y++)    {      for (x=5.5; x<=12.5;x=x+0.5)       {         i=2 + (y+ (0.5*x)) ;         printf("\n i=%.2f, y=%d, x=%.2f", i, y, x);       }    } } output:  i=5.75, y=1, x=5.50  i=6.00, y=1, x=6.00  i=6.25, y=1, x=6.50  i=6.50, y=1, x=7.00  i=6.75, y=1, x=7.50  i=7.00, y=1, x=8.00  i=7.25, y=1, x=8.50  i=7.50, y=1, x=9.00  i=7.75, y=1, x=9.50  i=8.00, y=1, x=10.00...

Write a program to find the range of a set of numbers. Range is the difference between the smallest and biggest number in the list.

#include<stdio.h> main() {        int elme,i,num,n,large,small,Range;     printf("Total Number of Element:");     scanf("%d",&elme);     printf("Enter first number=");     scanf("%d",&n);     large=n;     small=n;     for(i=1;i<=elme-1;i++)     {         printf("Enter another Number=");         scanf("%d",&n);                 if(n>large)         large=n;         if(n<small)         small=n;     }     printf("Largest=%d\n",large);     printf("Smallest=%d\n",small);     Range=large-small;     printf("Range=%d",Range); } OUTPUT: T...

Given the coordinates (x, y) of a center of a circle and it’s radius, write a program which will determine whether a point lies inside the circle, on the circle or outside the circle.

C Programm: #include<stdio.h> main() { int x,y,r; int di,ra; printf("Enter the value of x and y:"); scanf("%d %d",&x,&y); printf("Enter the radius:"); scanf("%d",&r); di=x^2+y^2; ra=r^2; if(di==r) printf("Point on the Circle"); else if(di>r) printf("Point outside the Circle"); else if(di<r) printf("Point inside the Circle"); } Math:The distance between ⟨ x c , y c ⟩ and ⟨ x p , y p ⟩ is given by the Pythagorean theorem as d = ( x p − x c ) 2 + ( y p − y c ) 2 − − − − − − − − − − − − − − − − − − √ . The point ⟨ x p , y p ⟩ is inside the circle if d < r , on the circle if d = r , and outside the circle if d > r . You can save yourself a little work by comparing d 2 with r 2 instead: the point is inside the circle if d 2 < r 2 , on the circle if d 2 = r 2 , and outside the circle if d 2 > r 2 . Thus, you want to compare the number ( x p − x c ) 2 + ( y p − y c ) 2 with...

Bsc viva

VIVA FOR VALUE OF 'G' Q.1 what is g? A.1 acceleration due to gravity. Q.2 What is bar pendulum? A.2 A bar pendulum is a long iron rod, which uses in the experiment of which one of the edges is fixed to move to and fro and frictionless. Q.3 What is a simple pendulum. A.3 A simple pendulum is one which can be considered to be a point mass suspended from a string or rod of negligible mass. Q.4 The value of g at pole and equator? A.4 g=more than 9.8 at the pole and more than 9.7 at the equator. Q.5 The relation between 'g' and 'G'.  A.5 g=GM/R square. VIVA FOR L-C-R CIRCUIT Q.1 Definition of A.C current A.1 The electric charge periodically in reverse direction called a.c Q.2 Direct current? A.2 The electric charge only one direction called D.C. Q.3 What is Capacitance? A.3 Capacity of store electric charge called capacitance. Q.4 What is Capacitor? A.4 Stored of electric charge called capacitor. Q.5 What is Inductance? A.5 In electromagne...